191 lines
5.2 KiB
C#
191 lines
5.2 KiB
C#
//
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// Copyright 2012 Hakan Kjellerstrand
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//
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// Licensed under the Apache License, Version 2.0 (the "License");
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// you may not use this file except in compliance with the License.
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// You may obtain a copy of the License at
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//
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// http://www.apache.org/licenses/LICENSE-2.0
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//
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// Unless required by applicable law or agreed to in writing, software
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// distributed under the License is distributed on an "AS IS" BASIS,
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// WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
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// See the License for the specific language governing permissions and
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// limitations under the License.
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using System;
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using System.Collections;
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using System.IO;
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using System.Text.RegularExpressions;
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using Google.OrTools.ConstraintSolver;
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public class DivisibleBy9Through1
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{
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/**
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*
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* A simple propagator for modulo constraint.
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*
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* This implementation is based on the ECLiPSe version
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* mentioned in "A Modulo propagator for ECLiPSE"
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* http://www.hakank.org/constraint_programming_blog/2010/05/a_modulo_propagator_for_eclips.html
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* The ECLiPSe Prolog source code:
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* http://www.hakank.org/eclipse/modulo_propagator.ecl
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*
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*/
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public static void MyMod(Solver solver, IntVar x, IntVar y, IntVar r)
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{
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long lbx = x.Min();
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long ubx = x.Max();
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long ubx_neg = -ubx;
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long lbx_neg = -lbx;
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int min_x = (int)Math.Min(lbx, ubx_neg);
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int max_x = (int)Math.Max(ubx, lbx_neg);
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IntVar d = solver.MakeIntVar(min_x, max_x, "d");
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// r >= 0
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solver.Add(r >= 0);
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// x*r >= 0
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solver.Add(x * r >= 0);
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// -abs(y) < r
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solver.Add(-y.Abs() < r);
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// r < abs(y)
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solver.Add(r < y.Abs());
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// min_x <= d, i.e. d > min_x
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solver.Add(d > min_x);
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// d <= max_x
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solver.Add(d <= max_x);
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// x == y*d+r
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solver.Add(x - (y * d + r) == 0);
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}
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/**
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*
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* ToNum(solver, a, num, base)
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*
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* channelling between the array a and the number num
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*
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*/
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private static Constraint ToNum(IntVar[] a, IntVar num, int bbase)
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{
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int len = a.Length;
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IntVar[] tmp = new IntVar[len];
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for (int i = 0; i < len; i++)
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{
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tmp[i] = (a[i] * (int)Math.Pow(bbase, (len - i - 1))).Var();
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}
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return tmp.Sum() == num;
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}
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/**
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*
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* Solves the divisible by 9 through 1 problem.
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* See http://www.hakank.org/google_or_tools/divisible_by_9_through_1.py
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*
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*/
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private static void Solve(int bbase)
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{
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Solver solver = new Solver("DivisibleBy9Through1");
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int m = (int)Math.Pow(bbase, (bbase - 1)) - 1;
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int n = bbase - 1;
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String[] digits_str = { "_", "0", "1", "2", "3", "4", "5", "6", "7", "8", "9" };
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Console.WriteLine("base: " + bbase);
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//
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// Decision variables
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//
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// digits
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IntVar[] x = solver.MakeIntVarArray(n, 1, bbase - 1, "x");
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// the numbers. t[0] contains the answe
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IntVar[] t = solver.MakeIntVarArray(n, 0, m, "t");
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//
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// Constraints
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//
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solver.Add(x.AllDifferent());
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// Ensure the divisibility of base .. 1
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IntVar zero = solver.MakeIntConst(0);
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for (int i = 0; i < n; i++)
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{
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int mm = bbase - i - 1;
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IntVar[] tt = new IntVar[mm];
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for (int j = 0; j < mm; j++)
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{
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tt[j] = x[j];
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}
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solver.Add(ToNum(tt, t[i], bbase));
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MyMod(solver, t[i], solver.MakeIntConst(mm), zero);
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}
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//
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// Search
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//
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DecisionBuilder db = solver.MakePhase(x, Solver.INT_VAR_DEFAULT, Solver.INT_VALUE_DEFAULT);
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solver.NewSearch(db);
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while (solver.NextSolution())
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{
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Console.Write("x: ");
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for (int i = 0; i < n; i++)
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{
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Console.Write(x[i].Value() + " ");
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}
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Console.WriteLine("\nt: ");
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for (int i = 0; i < n; i++)
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{
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Console.Write(t[i].Value() + " ");
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}
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Console.WriteLine("\n");
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if (bbase != 10)
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{
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Console.Write("Number base 10: " + t[0].Value());
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Console.Write(" Base " + bbase + ": ");
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for (int i = 0; i < n; i++)
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{
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Console.Write(digits_str[(int)x[i].Value() + 1]);
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}
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Console.WriteLine("\n");
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}
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}
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Console.WriteLine("\nSolutions: {0}", solver.Solutions());
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Console.WriteLine("WallTime: {0}ms", solver.WallTime());
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Console.WriteLine("Failures: {0}", solver.Failures());
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Console.WriteLine("Branches: {0} ", solver.Branches());
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solver.EndSearch();
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}
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public static void Main(String[] args)
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{
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int bbase = 10;
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if (args.Length > 1)
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{
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bbase = Convert.ToInt32(args[1]);
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if (bbase > 12)
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{
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// Though base = 12 has no solution...
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Console.WriteLine("Sorry, max relevant base is 12. Setting base to 12.");
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bbase = 10;
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}
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}
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Solve(bbase);
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}
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}
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