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ortools-clone/examples/contrib/divisible_by_9_through_1.cs
2022-09-05 17:38:11 +02:00

191 lines
5.2 KiB
C#

//
// Copyright 2012 Hakan Kjellerstrand
//
// Licensed under the Apache License, Version 2.0 (the "License");
// you may not use this file except in compliance with the License.
// You may obtain a copy of the License at
//
// http://www.apache.org/licenses/LICENSE-2.0
//
// Unless required by applicable law or agreed to in writing, software
// distributed under the License is distributed on an "AS IS" BASIS,
// WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
// See the License for the specific language governing permissions and
// limitations under the License.
using System;
using System.Collections;
using System.IO;
using System.Text.RegularExpressions;
using Google.OrTools.ConstraintSolver;
public class DivisibleBy9Through1
{
/**
*
* A simple propagator for modulo constraint.
*
* This implementation is based on the ECLiPSe version
* mentioned in "A Modulo propagator for ECLiPSE"
* http://www.hakank.org/constraint_programming_blog/2010/05/a_modulo_propagator_for_eclips.html
* The ECLiPSe Prolog source code:
* http://www.hakank.org/eclipse/modulo_propagator.ecl
*
*/
public static void MyMod(Solver solver, IntVar x, IntVar y, IntVar r)
{
long lbx = x.Min();
long ubx = x.Max();
long ubx_neg = -ubx;
long lbx_neg = -lbx;
int min_x = (int)Math.Min(lbx, ubx_neg);
int max_x = (int)Math.Max(ubx, lbx_neg);
IntVar d = solver.MakeIntVar(min_x, max_x, "d");
// r >= 0
solver.Add(r >= 0);
// x*r >= 0
solver.Add(x * r >= 0);
// -abs(y) < r
solver.Add(-y.Abs() < r);
// r < abs(y)
solver.Add(r < y.Abs());
// min_x <= d, i.e. d > min_x
solver.Add(d > min_x);
// d <= max_x
solver.Add(d <= max_x);
// x == y*d+r
solver.Add(x - (y * d + r) == 0);
}
/**
*
* ToNum(solver, a, num, base)
*
* channelling between the array a and the number num
*
*/
private static Constraint ToNum(IntVar[] a, IntVar num, int bbase)
{
int len = a.Length;
IntVar[] tmp = new IntVar[len];
for (int i = 0; i < len; i++)
{
tmp[i] = (a[i] * (int)Math.Pow(bbase, (len - i - 1))).Var();
}
return tmp.Sum() == num;
}
/**
*
* Solves the divisible by 9 through 1 problem.
* See http://www.hakank.org/google_or_tools/divisible_by_9_through_1.py
*
*/
private static void Solve(int bbase)
{
Solver solver = new Solver("DivisibleBy9Through1");
int m = (int)Math.Pow(bbase, (bbase - 1)) - 1;
int n = bbase - 1;
String[] digits_str = { "_", "0", "1", "2", "3", "4", "5", "6", "7", "8", "9" };
Console.WriteLine("base: " + bbase);
//
// Decision variables
//
// digits
IntVar[] x = solver.MakeIntVarArray(n, 1, bbase - 1, "x");
// the numbers. t[0] contains the answe
IntVar[] t = solver.MakeIntVarArray(n, 0, m, "t");
//
// Constraints
//
solver.Add(x.AllDifferent());
// Ensure the divisibility of base .. 1
IntVar zero = solver.MakeIntConst(0);
for (int i = 0; i < n; i++)
{
int mm = bbase - i - 1;
IntVar[] tt = new IntVar[mm];
for (int j = 0; j < mm; j++)
{
tt[j] = x[j];
}
solver.Add(ToNum(tt, t[i], bbase));
MyMod(solver, t[i], solver.MakeIntConst(mm), zero);
}
//
// Search
//
DecisionBuilder db = solver.MakePhase(x, Solver.INT_VAR_DEFAULT, Solver.INT_VALUE_DEFAULT);
solver.NewSearch(db);
while (solver.NextSolution())
{
Console.Write("x: ");
for (int i = 0; i < n; i++)
{
Console.Write(x[i].Value() + " ");
}
Console.WriteLine("\nt: ");
for (int i = 0; i < n; i++)
{
Console.Write(t[i].Value() + " ");
}
Console.WriteLine("\n");
if (bbase != 10)
{
Console.Write("Number base 10: " + t[0].Value());
Console.Write(" Base " + bbase + ": ");
for (int i = 0; i < n; i++)
{
Console.Write(digits_str[(int)x[i].Value() + 1]);
}
Console.WriteLine("\n");
}
}
Console.WriteLine("\nSolutions: {0}", solver.Solutions());
Console.WriteLine("WallTime: {0}ms", solver.WallTime());
Console.WriteLine("Failures: {0}", solver.Failures());
Console.WriteLine("Branches: {0} ", solver.Branches());
solver.EndSearch();
}
public static void Main(String[] args)
{
int bbase = 10;
if (args.Length > 1)
{
bbase = Convert.ToInt32(args[1]);
if (bbase > 12)
{
// Though base = 12 has no solution...
Console.WriteLine("Sorry, max relevant base is 12. Setting base to 12.");
bbase = 10;
}
}
Solve(bbase);
}
}